Postal Examination 2015 on FaceBook

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UPSC Advt No 02/2016 for Various Vacancies


UPSC Advt No 02/2016 for Various Vacancies: Union Public Service Commission (UPSC) has issued notification for Various Vacancies.

Name of the Posts:

  • Assistant Library and Information Officer: 01 Post
    • Age: 30 years
  • Civilian Medical Officers: 49 Posts
    • Age: 35 years
  • Specialist Grade-III Assistant Professor (Cancer Surgery): 01 Post
    • Age: 40 years
  • Specialist Grade-III Assistant Professors (Urology): 02 Posts
    • Age: 40 years
  • Specialist Grade-III Assistant Professors (Gastroenterology): 08 Posts
    • Age: 40 years
  • Specialist Grade-III Assistant Professors (Endocrinology): 09 Posts
    • Age: 40 years
  • Specialist Grade-III (Neurology): 01 Post
    • Age: 40 years
  • Specialist Grade-III (Cardiology): 01 Post
    • Age: 40 years
  • Specialist Grade-III Assistant Professors (Plastic Surgery): 08 Posts
    • Age: 40 years
  • Specialist Grade-III Assistant Professors ( Psychiatry): 26 Posts
    • Age: 40 years
  • Specialist Grade-III Assistant Professors (Pediatric Cardiology): 02 Posts
    • Age: 40 years
  • Assistant Employment Officer: 01 Post
    • Age: 30 years
  • Chemist in Indian Bureau of Mines: 01 Post
    • Age: 35 years
  • Economic Officers: 02 Posts
    • Age: 30 years
Total No. of Posts : 112 Posts

Educational Qualification : Please read Official Notification for Educational Qualification details.

Selection Process: Selection will based on recruitment test followed by interview.

Application Fee:
  • Candidates are required to pay a fee of Rs. 25/- (Rupees Twenty five) only either by remitting the money in any branch of the SBI by cash or by using net banking facility of the SBI or by using visa/master credit/debit card.
  • No fee for SC/ST/PH/Women candidates of any community. No "fee exemption" is available to OBC male candidates and they are required to pay the full prescribed fee.
  • Applications without the prescribed fee would not be considered and summarily rejected. No representation against such rejection would be entertained.
  • Fee once paid shall not be refunded under any circumstance nor can the fee be held in reserve for any other examination or selection

How to Apply: Eligible Candidates must apply online through the website http://www.upsconline.nic.in & & Candidates must upload documents pertaining to educational qualification(s) and experience (preferably in prescribed format), if any, as claimed in the online application, in a single pdf file in such a way that the file size does not exceed 2 MB and is legible when a printout taken. For that the applicant may scan the experience certificate in 200 dpi grey scale. Documents like Pay Slip, Resume, Appointment Letter, Relieving Letter, Un-signed Experience Certificate etc. must not be uploaded in the Document Upload Module.


Important Dates:
Closing Date for Submission of Online Application: 11-02-2016 up to 23:59 hrs
Last Date for Printing of Completely Submitted Online Application: 12-02-2016 up to 23:59 hrs

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Apply Online : Click Here
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India Post is going to announce about 20000 vacancies soon


Great news for all the government jobs aspirants as Indian Postal department is going to announce one of the biggest employment notifications very soon. The recruitment will be organized for selection of eligible staff for Postal Assistant and Sorting Assistant posts on its official site www.indiapost.gov.in. Now all those qualified candidates are invited for 20000 upcoming job opening whose link will be soon available at their official site. This notification will bring good news for those entire aspirants who were looking for government jobs, 10th pass government jobs, 12th pass government jobs, post office jobs etc.

According to report, India post is going to hire candidates for Postal Assistant and Sorting Assistant posts, Stenographers, Postman and Mail Guard, MTS, Postmaster Cadres, Hindi Typist, Inspector, Director Posts, etc. Aspirant must have completed their Matriculation or Intermediate from recognized board and diploma/ graduation/ bachelors or its equivalent in required discipline from recognized university or institute. The online application process will start from February 2016 and will going to end on March 2016.

India Post operates postal system in India. It was founded during British Empire i.e. 01st April, 1774 and operated under Ministry of Communication and Information Technology, Govt of India. But, on 31st March 2011 it was officially declared as the Indian Postal Service and currently has more than 154,866 post offices which are located across India. Main headquarter of post office is located in Sansad Marg, New Delhi.


India post is popular among candidates for providing various services such as Letter post, parcel service, EMS, deposit account, third-party logistics freight forwarding, delivery etc. India post is divided into 22 postal circles which is independently headed by chief postmaster general. Currently more than 4, 70,000 employees are working with Indian postal circle. India Post’s main objective is to provide all type of courier service at low cost than other private firm. For the date of official announcement keep going through their official website daily and stay tuned with us for more news related to latest government job vacancy.
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Vacancy in Postal Assistant Cadre Andhra pradesh circle

Vacancy in Postal Assistant Cadre (DIRECT RECRUIT / LGO / GDS TO PA)

LGO VACANCIES 2015-2016

FOR THE VACANCIES OF THE YEAR 2015-16 PERTAINING TO LIMITED DEPARTMENTAT COMPETETlVE EXAMINATION (LGO-2015-16) TO THE CADRE OF POSTAL ASSTSTANTS /SORTING ASSTSTANTS (50%PROMOTIONAL QUOTA) .-.
POSTAL ASSISTANT ..222
SORTING ASSISTANT...54
TOTAL ...276
CATEGORY.WISE VACANCY POSITION OF DIVISIONS IN A.P. CIRCLE

CLICK HERE TO SEE DIVISION WISE VACANCIES

DIRECT RECRUITMENT VACANCY POSITION 

OF PA /SA / PA SBCO / PA {CO/RO} / PA MMS FOR THE YEAR 2015-16
POSTAL ASSISTANT--175
SORTING ASSISTANT--44
PA (CO/RO)--10
PASBCO---9
PA MMS--1
TOTAL VACANCIES: 239


GDS TO PA VACANCIES

UNFILLED VACANCIES OF LGO - 2013 TO BE OFFERED TO GDS ALONG WITH DR-2015-16
GDS TO PA VACANCIES: 62
GDS TO SA VACANCIES: 37
VIJAYAWADA ..OC-2 OBC-1

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BIDHYA BHANDARI BECOMES NEPAL'S FIRST WOMAN PRESIDENT

Bindhya_bhandari


Bidhya Bhandari was elected as Nepal's first woman president today, after the adoption of a landmark constitution last month.


Ms Bhandari, currently the vice-chair of the ruling Communist Party of Nepal (Unified Marxist Leninist), defeated her opponent Kul Bahadur Gurung of the Nepali Congress by securing 327 to 214 votes to become the Himalayan nation's ceremonial head of state.

She is the second person to hold the mainly ceremonial role.
The 54-year-old is currently the vice-chair of the ruling Communist Party of Nepal (United Marxist Leninist).
Ms Bhandari was defence minister from 2009 to 2011. As president, she has promised to champion minority and women's rights in Nepal.
According to parliament officials, 549 of the total 597 lawmakers took part in the election. Forty-eight others including those from Madhesi parties protesting against the new constitution abstained.
Bhandari, who was elected a month after the country adopted the statute, will replace Ram Baran Yadav, Nepal’s first head of state after monarchy was abolished in 2008.
A communist with over three decades of political experience since her student days, Bhandari had withdrawn from active politics after getting married to CPN-UML general secretary Madan Bhandari.
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MENTAL MATH TRICKS FOR DIVISION- BASICS FOR EXAMS

Quantitative Aptitude and Data Interpretation sections of various competitive exams call for long, time-intensive calculations. The time you spend here could mean the difference between selection and disqualification. Calculations can be made easier using divisibility tests and mental math tricks for division specially. You can even use these mental tricks of maths for division to eliminate options. These tricks will be useful for all competitive exams including IBPS Clerk, SBI Clerk, IBPS PO, SBI PO, IBPS RRB, SSC CGL, CAT, XAT, Placement Aptitude, NICL AO, LIC AAO, SBI Associate Clerk, and SBI Associate PO.

Note: In every divisibility test, please assume that 0 is divisible by all divisors.

Divisibility Test for 2

A number is divisible by 2 if the last digit is divisible by 2 i.e. last digit is 0, 2, 4, 6 or 8.
E.g. 864 is divisible by 2 since the last digit 4 is divisible by 2.


Divisibility Test for 3

A number is divisible by 3 if the sum of the digits of the number is divisible by 3.
E.g. 861 is divisible by 3 since the sum of the digits is 15 (8 + 6 + 1 = 15), and 15 is divisible by 3.


Divisibility Test for 4

A number is divisible by 4 if the number formed by the last two digits is divisible by 4.
E.g. 504 is divisible by 4 since 04 is divisible by 4.

Divisibility Test for 5

A number is divisible by 5 if the last digit is either 0 or 5.
E.g. 425 is divisible by 5 since the last digit is 5.


Divisibility Test for 6

A number is divisible by 6 if it is divisible by 2 AND it is divisible by 3.
E.g. 186 is divisible by 6 since it is divisible by 2 AND it is divisible by 3.

Divisibility Test for 7

To find out if a number is divisible by 7 or not, follow these steps:
1. Separate the last digit from the rest of the number. Let us call the rest of the number the truncated number. The truncated number has one less digit than the original number or the previous truncated number.
2. Double the last digit and subtract it from the truncated number.
3. Check if this result is sufficiently small so that you can immediately say if this is divisible by 7. If it is divisible by 7, then so was the original number. If it is not divisible by 7, then neither was the original number.
4. If the number is still too large to visually check if it is divisible, apply this rule over and over again as necessary.
E.g. Check 6132. The last digit is 2 and the truncated number is 613. Twice of 2 is 4. So subtract 4 from the truncated number 613 i.e. 613 – 4 = 609. Again, the last digit is now 9, and the truncated number is 60. Twice of 9 is 18. Subtract it from the truncated number 60, i.e. 60 – 18 = 42. Now 42 is small enough to check visually. We know that 42 is divisible by 7, so we can tell that 6132 is divisible by 7 also.
division


NOTE: Explaining this step is long. But actually using it is a very short and time saving method. This method is especially useful in Geometry and Mensuration problems where the value of π plays an important role.

Divisibility Test for 8

A number is divisible by 8 if the number formed by the last three digits is divisible by 8.
E.g. 8120 is divisible by 8 since 120 is divisible by 8.

Divisibility Test for 9

A number is divisible by 9 if the sum of its digits is divisible by 9. If the sum is large, you can once again add the digits and check if the new sum is divisible by 9.
E.g. 27549 is divisible by 9 since the sum of the digits is 27 (2 + 7 + 5 + 4 + 9 = 27), and 27 is divisible by 9.

Divisibility Test for 10

A number is divisible by 10 if the last digit is 0.
E.g. 1760 is divisible by 10 since the last digit is 0.

Divisibility Test for 11

Method 1:- The (sum of the odd place digits) – (sum of the even place digits) is divisible by 11.
E.g. 963391
Sum of odd place digits = 9 + 3 + 9 = 21
Sum of even place digits = 6 + 3 + 1 = 10
Difference = 21 – 10 = 11 which is divisible by 11.
So, yes, 963391 is divisible by 11.
Method 2: Subtract the last digit from the remaining truncated number. If the result is divisible by 11, then so was the first number. Apply this rule over and over again as necessary.
E.g. 963391 → 96339 – 1 = 96338 → 9633 – 8 = 9625 → 962 – 5 = 957 → 95 – 7 = 88, which is divisible by 11. So yes, 963391 is divisible by 11.


Divisibility Test for 13

To find out if a number is divisible by 13 or not, follow these steps:
  1. Separate the last digit from the rest of the number. Let us call the rest of the number the truncated number. The truncated number has one less digit than the original number or the previous truncated number.
  2. Multiply the last digit by 4 and add it to the truncated number.
  3. Check if this result is sufficiently small so that you can immediately say if this is divisible by 13. If it is divisible by 13, then so was the original number. If it is not divisible by 13, then neither was the original number.
  4. If the number is still too large to visually check if it is divisible, apply this rule over and over again as necessary.
E.g. 12675 → 1267 + 20 = 1287 → 128 + 28 = 156 → 15 + 24 = 39, which is divisible by 13. So yes, 12675 is divisible by 13.


Divisibility Test for 17

To find out if a number is divisible by 17 or not, follow these steps:
  1. Separate the last digit from the rest of the number. Let us call the rest of the number the truncated number. The truncated number has one less digit than the original number or the previous truncated number.
  2. Multiply the last digit by 5 and subtract it from the truncated number.
  3. Check if this result is sufficiently small so that you can immediately say if this is divisible by 17. If it is divisible by 17, then so was the original number. If it is not divisible by 17, then neither was the original number.
  4. If the number is still too large to visually check if it is divisible, apply this rule over and over again as necessary.
E.g. 21165 → 2116 – 25 = 2091 → 209 – 5 = 204 → 20 – 20 = 0, which is divisible by 17. So yes, 21165 is divisible by 17.


Divisibility Test for 19

Add two times the last digit to the remaining leading truncated number. If the result is divisible by 19, then so was the first number. Apply this rule over and over again as necessary.
E.g. 185117 → 18511 + 2 × 7 = 18525 → 1852 + 2 × 5 = 1862 → 186 + 2 × 2 = 190, which is divisible by 19. So yes, 185117 is divisible by 19.



Divisibility Test for Composites

A number is divisible by a composite if it is also divisible by all the prime factors.
E.g. 157905 is divisible by 33 if it is divisible by 3 AND by 11.

Hope you liked our effort and we are sure that these mental math tricks for division will help you a lot in exams. Well, there are already a number of books related to the basics of division but they look messy. Here I have complied only important tricks of division that everyone should know. Yes you are free to learn more and more because nothing is enough if we talk about competitive exam. Good Luck!
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